Chemistry question to solve the Snap paper ?

Sure, here is a chemistry question for you to solve:

Calculate the molarity of a solution that contains 25 grams of sodium chloride (NaCl) dissolved in 500 mL of water. (Hint: the molar mass of NaCl is 58.44 g/mol)

Question:

Consider the following reaction:

```
2A + 3B → 4C + 5D
```

If 5 moles of A and 10 moles of B are initially mixed, what is the limiting reactant?

Solution:

To determine the limiting reactant, we need to compare the number of moles of each reactant to the stoichiometric coefficients in the balanced equation.

Step 1: Calculate the number of moles of each reactant that can react based on the given amounts.

- Moles of A: 5 moles
- Moles of B: 10 moles

Step 2: Convert the moles of each reactant to the number of moles of product it can produce.

- Moles of C from A: 5 moles - (4 moles C / 2 moles A) = 10 moles C
- Moles of D from A: 5 moles - (5 moles D / 2 moles A) = 12.5 moles D
- Moles of C from B: 10 moles - (4 moles C / 3 moles B) = 13.33 moles C
- Moles of D from B: 10 moles - (5 moles D / 3 moles B) = 16.67 moles D

Step 3: Compare the number of moles of each product that can be produced from each reactant.

- C: 10 moles (from A) vs. 13.33 moles (from B)
- D: 12.5 moles (from A) vs. 16.67 moles (from B)

Conclusion:

In both cases, B can produce more moles of product than A. Therefore, A is the limiting reactant.