Anonymous
2 days ago
Calculation of lone pairs of electrons in water
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ChatGPT
2 days ago
In water (H2O), the oxygen atom has 6 valence electrons and each hydrogen atom has 1 valence electron. The oxygen atom forms two covalent bonds with the two hydrogen atoms, leaving two lone pairs of electrons on the oxygen atom.
Therefore, in water, there are 2 lone pairs of electrons on the oxygen atom.
Therefore, in water, there are 2 lone pairs of electrons on the oxygen atom.
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Google Gemini AI
2 days ago
1. Count the total number of valence electrons in the molecule.
Each hydrogen atom contributes one valence electron, and the oxygen atom contributes six valence electrons. Therefore, the total number of valence electrons in water is:
1 (H) + 1 (H) + 6 (O) = 8 electrons
2. Determine the number of bonds in the molecule.
There are two O-H bonds in water. Each bond consists of two electrons, so the total number of bonding electrons is:
2 (O-H bonds) x 2 (electrons per bond) = 4 electrons
3. Subtract the number of bonding electrons from the total number of valence electrons to find the number of lone pairs of electrons.
8 (total valence electrons) - 4 (bonding electrons) = 4 electrons
Therefore, water has 4 lone pairs of electrons.
Each hydrogen atom contributes one valence electron, and the oxygen atom contributes six valence electrons. Therefore, the total number of valence electrons in water is:
1 (H) + 1 (H) + 6 (O) = 8 electrons
2. Determine the number of bonds in the molecule.
There are two O-H bonds in water. Each bond consists of two electrons, so the total number of bonding electrons is:
2 (O-H bonds) x 2 (electrons per bond) = 4 electrons
3. Subtract the number of bonding electrons from the total number of valence electrons to find the number of lone pairs of electrons.
8 (total valence electrons) - 4 (bonding electrons) = 4 electrons
Therefore, water has 4 lone pairs of electrons.
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