Calculate the x values of the following Quadratic functions? y=x^2-7x-8?

To find the x values of the quadratic function y=x^2-7x-8, we need to set y equal to 0 and solve for x.

0 = x^2 - 7x - 8

Now, we can factor the quadratic equation or use the quadratic formula to find the x values.

Factoring:
0 = (x - 8)(x + 1)

Setting each factor equal to zero:
x - 8 = 0
x = 8

x + 1 = 0
x = -1

Therefore, the x values of the quadratic function y=x^2-7x-8 are x = 8 and x = -1.

The x-values of a quadratic function are the values of the independent variable x at which the function has a maximum or minimum value. These values can be found by setting the derivative of the function equal to zero and solving for x.

For the quadratic function y=x^2-7x-8, the derivative is:

```
y' = 2x - 7
```

Setting the derivative equal to zero and solving for x, we get:

```
2x - 7 = 0
2x = 7
x = 7/2
```

Therefore, the x-value of the quadratic function y=x^2-7x-8 at which the function has a maximum or minimum value is x = 7/2.