Calculate the volume of hydrogen chloride formed at STP. (Given: Cl = 35.5, H = 1, 1 mole of a gas occupies 22.4 liters at STP)

To calculate the volume of hydrogen chloride formed at STP, we first need to determine the molar ratio of hydrogen and chlorine in hydrogen chloride.

The chemical formula for hydrogen chloride is HCl, which means it contains one hydrogen atom and one chlorine atom. Therefore, the molar ratio of hydrogen to chlorine in hydrogen chloride is 1:1.

Now, let's assume we have 1 mole of hydrogen chloride formed. Since the molar ratio of hydrogen to chlorine is 1:1, this means we also have 1 mole of hydrogen and 1 mole of chlorine reacting to form 1 mole of hydrogen chloride.

At STP, 1 mole of any gas occupies 22.4 liters. Therefore, 1 mole of hydrogen chloride will occupy 22.4 liters.

So, the volume of hydrogen chloride formed at STP is 22.4 liters.

According to the balanced chemical equation:

2HCl → H2 + Cl2

2 moles of HCl produce 1 mole of H2

Volume of 1 mole of gas at STP = 22.4 liters

Step 1: Calculate the molar mass of HCl

Molar mass of HCl = Atomic mass of H + Atomic mass of Cl
Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

Step 2: Calculate the mass of HCl required to produce 1 mole of H2

From the balanced equation:

2 moles of HCl = 73 g (2 x 36.5 g/mol)

Step 3: Calculate the volume of HCl produced at STP

Volume of 73 g of HCl = (73 g / 36.5 g/mol) x 22.4 L/mol = 44.8 L

Therefore, the volume of hydrogen chloride formed at STP is 44.8 liters.