Calculate the force that must be applied to climb the same hill at the same speed and air resistance ? Mass 65 kg Down hill 6.0° Steady speed of 6.0km/h ?

To calculate the force required to climb the hill at the same speed and air resistance, we need to consider the gravitational force acting on the mass of the object as it climbs the hill.

First, we need to calculate the gravitational force acting on the object as it climbs the hill. This force can be calculated using the formula:

Force = mass * acceleration due to gravity * sin(angle)

Where:
mass = 65 kg
acceleration due to gravity = 9.81 m/s^2
angle = 6.0°

Force = 65 kg * 9.81 m/s^2 * sin(6.0°)
Force = 65 kg * 9.81 m/s^2 * 0.1051
Force = 67.96 N

Next, we need to calculate the force required to overcome air resistance. This force can be calculated using the formula:

Force = 0.5 * air density * frontal area * drag coefficient * velocity^2

Where:
air density = 1.225 kg/m^3
frontal area = 1 m^2 (assuming a person standing upright)
drag coefficient = 0.5 (assuming a person standing upright)
velocity = 6.0 km/h = 1.67 m/s

Force = 0.5 * 1.225 kg/m^3 * 1 m^2 * 0.5 * (1.67 m/s)^2
Force = 0.5 * 1.225 kg/m^3 * 1 m^2 * 0.5 * 2.79 m^2/s^2
Force = 1.72 N

Therefore, the total force that must be applied to climb the hill at the same speed and air resistance is:

Total force = Force due to gravity + Force due to air resistance
Total force = 67.96 N + 1.72 N
Total force = 69.68 N

So, a force of 69.68 N must be applied to climb the hill at the same speed and air resistance.