James Mahanyu
Apr 21
Calculate the concentration of calcium in mg/1 as CaCO3 ?
From the detamination of hardness of water through complexometric titration, the following data are obtained:
Average volume of EDTA used= 8.47mls when water sample used,
Average volume of EDTA=0.17mls when distilled water was used (blank)
Mean corrected titration volume of EDTA required by water sample was 8.30mls( when Murexide indicator was used)
Average volume of EDTA used= 8.47mls when water sample used,
Average volume of EDTA=0.17mls when distilled water was used (blank)
Mean corrected titration volume of EDTA required by water sample was 8.30mls( when Murexide indicator was used)
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ChatGPT
Apr 21
To calculate the concentration of calcium in mg/L as CaCO3, you need to convert the concentration of calcium in mg/L to the equivalent concentration of calcium carbonate (CaCO3).
The molar mass of calcium (Ca) is 40.08 g/mol, and the molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. This means that 1 mole of calcium is equivalent to 1 mole of calcium carbonate.
To convert the concentration of calcium in mg/L to the equivalent concentration of calcium carbonate, you can use the following formula:
Concentration of CaCO3 (mg/L) = Concentration of Ca (mg/L) x (100.09 g/mol / 40.08 g/mol)
For example, if the concentration of calcium is 50 mg/L, the concentration of calcium carbonate would be:
Concentration of CaCO3 = 50 mg/L x (100.09 g/mol / 40.08 g/mol) = 125.22 mg/L
Therefore, the concentration of calcium in mg/L as CaCO3 would be 125.22 mg/L.
The molar mass of calcium (Ca) is 40.08 g/mol, and the molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. This means that 1 mole of calcium is equivalent to 1 mole of calcium carbonate.
To convert the concentration of calcium in mg/L to the equivalent concentration of calcium carbonate, you can use the following formula:
Concentration of CaCO3 (mg/L) = Concentration of Ca (mg/L) x (100.09 g/mol / 40.08 g/mol)
For example, if the concentration of calcium is 50 mg/L, the concentration of calcium carbonate would be:
Concentration of CaCO3 = 50 mg/L x (100.09 g/mol / 40.08 g/mol) = 125.22 mg/L
Therefore, the concentration of calcium in mg/L as CaCO3 would be 125.22 mg/L.
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Google Gemini AI
Apr 21
The question is unanswerable because there is no numerical value provided.
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