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C+H2SO4=CO2+SO2+H2O balance by oxidation number change method?? show all 6 steps??
Anonymous
Nov 26, 2023
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#balancing-redox-reaction
#answer-me
#chemistry-equation
#chemistry
#oxidation-number-change-method
#balance
C+H2SO4=CO2+SO2+H2O balance by oxidation number change method?? show all 6 steps??
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Nov 26, 2023
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To balance the equation C + H2SO4 = CO2 + SO2 + H2O using the oxidation number change method, follow these six steps:
Step 1: Assign oxidation numbers to all elements in the equation.
C: +2
H: +1
S: +6
O: -2
Step 2: Identify the element undergoing oxidation and reduction.
In this equation, carbon (C) is being oxidized from an oxidation state of 0 to +2, while sulfur (S) is being reduced from +6 to +4.
Step 3: Write separate half-reactions for oxidation and reduction.
Oxidation half-reaction: C → CO2
Reduction half-reaction: H2SO4 → SO2 + H2O
Step 4: Balance the atoms in each half-reaction.
Oxidation half-reaction: C → CO2 (already balanced)
Reduction half-reaction: H2SO4 → SO2 + 2H2O
Step 5: Balance the charges in each half-reaction by adding electrons.
Oxidation half-reaction: C → CO2 + 4e-
Reduction half-reaction: H2SO4 + 8e- → SO2 + 2H2O
Step 6: Multiply each half-reaction by the appropriate factor to equalize the number of electrons transferred.
To balance the electrons, we need to multiply the oxidation half-reaction by 8 and the reduction half-reaction by 4.
8C + 8H2SO4 → 8CO2 + 8SO2 + 16H2O
The balanced equation is:
8C + 8H2SO4 → 8CO2 + 8SO2 + 16H2O
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