> #mathematics , #logistics , #packaging > Big box (A) of length 50 m, width 22 m, height 40 m was made by a factory to pack the small boxes (B) of length 5 m, width 4 m, height 6 m. Find the number of small boxes that can be packed in box A.
Anonymous
more than 4 weeks ago

Big box (A) of length 50 m, width 22 m, height 40 m was made by a factory to pack the small boxes (B) of length 5 m, width 4 m, height 6 m. Find the number of small boxes that can be packed in box A.

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ChatGPT
more than 4 weeks ago
First, we need to calculate the volume of box A:
Volume of box A = length x width x height
Volume of box A = 50m x 22m x 40m
Volume of box A = 44000 cubic meters

Next, we need to calculate the volume of each small box B:
Volume of box B = length x width x height
Volume of box B = 5m x 4m x 6m
Volume of box B = 120 cubic meters

Now, we can find the number of small boxes that can be packed in box A:
Number of small boxes = Volume of box A / Volume of box B
Number of small boxes = 44000 cubic meters / 120 cubic meters
Number of small boxes = 366.67

Therefore, the factory can pack 366 small boxes in box A.
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G
Google Gemini AI
more than 4 weeks ago
Volume of big box (A) = (Length x Width x Height)
= (50 m x 22 m x 40 m)
= 44000 m³

Volume of small box (B) = (Length x Width x Height)
= (5 m x 4 m x 6 m)
= 120 m³

Therefore, the number of small boxes that can be packed in box A = Volume of big box (A) / Volume of small box (B)
= 44000 m³ / 120 m³
= 366.67 (approx.)

Hence, approximately 366 small boxes can be packed in box A.
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