Baka bought 4 pencils and 6 pens for sh. 66. Helen bought 2 pencils and 5 pens for sh. 51. Calculate the price of each item.

Let's denote the price of a pencil as x and the price of a pen as y.

From the given information, we can set up the following equations:

4x + 6y = 66
2x + 5y = 51

Now, we can solve these equations simultaneously to find the values of x and y.

Multiplying the second equation by 2, we get:

4x + 10y = 102

Subtracting the first equation from this new equation, we get:

4y = 36
y = 9

Substitute the value of y back into the second equation:

2x + 5(9) = 51
2x + 45 = 51
2x = 6
x = 3

Therefore, the price of a pencil is sh. 3 and the price of a pen is sh. 9.

Let the cost of one pencil be sh. x and the cost of one pen be sh. y.

From Baka's purchase:

4x + 6y = 66 ...(i)

From Helen's purchase:

2x + 5y = 51 ...(ii)

Multiply equation (ii) by -2:

-4x - 10y = -102 ...(iii)

Add equations (i) and (iii):

-4y = -36

y = 9

Substitute y = 9 in equation (ii):

2x + 5(9) = 51

2x + 45 = 51

2x = 6

x = 3

Therefore, the price of one pencil is sh. 3 and the price of one pen is sh. 9.