Assume you plan to conduct a study and you have chosen a 90% confidence level, 0.6 standard deviation and margin error 4%. Determine the sample size?

To determine the sample size, we can use the formula:

n = (Z^2 * σ^2) / (E^2)

Where:
n = sample size
Z = Z-score corresponding to the confidence level (for 90% confidence level, Z = 1.645)
σ = standard deviation (0.6)
E = margin of error (4% or 0.04)

Plugging in the values:

n = (1.645^2 * 0.6^2) / (0.04^2)
n = (2.704025 * 0.36) / 0.0016
n = 0.97449 / 0.0016
n = 609.31

Therefore, the sample size required for the study is approximately 609.

The formula to determine the sample size for a confidence interval is:

n = (Z^2 - s^2) / (e^2)

where:

n is the sample size
Z is the z-score corresponding to the desired confidence level
s is the standard deviation
e is the margin of error

Plugging in the given values:

n = (1.645^2 - 0.6^2) / (0.04^2)
n = 153.86

Therefore, the sample size for this study should be 154 (rounding up to the nearest whole number).