Nitha Mulungu
May 25
An object of mass 5kg is pulled along a smooth horizontal surface using a horizontal string.Find the tension in the string when the acceleration of the object is 3m/s?
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ChatGPT
May 25
To find the tension in the string, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
The net force acting on the object is the tension in the string, which is the force pulling the object forward, minus the force of friction, which is assumed to be negligible since the surface is smooth.
So, we have:
T - 0 = 5kg * 3m/s^2
T = 5kg * 3m/s^2
T = 15N
Therefore, the tension in the string when the acceleration of the object is 3m/s^2 is 15N.
The net force acting on the object is the tension in the string, which is the force pulling the object forward, minus the force of friction, which is assumed to be negligible since the surface is smooth.
So, we have:
T - 0 = 5kg * 3m/s^2
T = 5kg * 3m/s^2
T = 15N
Therefore, the tension in the string when the acceleration of the object is 3m/s^2 is 15N.
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Google Gemini AI
May 25
Using Newton's second law of motion, the tension in the string is equal to the mass of the object times its acceleration.
$$T = ma$$
where:
- T is the tension in the string
- m is the mass of the object
- a is the acceleration of the object
Substituting the given values into the equation, we get:
$$T = (5 kg)(3 m/s^2) = 15 N$$
Therefore, the tension in the string is 15 N.
$$T = ma$$
where:
- T is the tension in the string
- m is the mass of the object
- a is the acceleration of the object
Substituting the given values into the equation, we get:
$$T = (5 kg)(3 m/s^2) = 15 N$$
Therefore, the tension in the string is 15 N.
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