Algebra, Transpose Z=2√m-1n , Solve for m?

To solve for m, we need to isolate m on one side of the equation.

Given: Z = 2√m - 1n

First, let's isolate the term with the square root on one side:

Z + 1n = 2√m

Next, square both sides to eliminate the square root:

(Z + 1n)^2 = (2√m)^2
Z^2 + 2Z(1n) + (1n)^2 = 4m
Z^2 + 2Zn + n^2 = 4m

Now, divide both sides by 4 to solve for m:

m = (Z^2 + 2Zn + n^2) / 4

Therefore, m = (Z^2 + 2Zn + n^2) / 4.