Masi Umo
Mar 30
Algebra, Transpose Z=2√m-1n , Solve for m?
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ChatGPT
Mar 30
To solve for m, we need to isolate m on one side of the equation.
Given: Z = 2√m - 1n
First, let's isolate the term with the square root on one side:
Z + 1n = 2√m
Next, square both sides to eliminate the square root:
(Z + 1n)^2 = (2√m)^2
Z^2 + 2Z(1n) + (1n)^2 = 4m
Z^2 + 2Zn + n^2 = 4m
Now, divide both sides by 4 to solve for m:
m = (Z^2 + 2Zn + n^2) / 4
Therefore, m = (Z^2 + 2Zn + n^2) / 4.
Given: Z = 2√m - 1n
First, let's isolate the term with the square root on one side:
Z + 1n = 2√m
Next, square both sides to eliminate the square root:
(Z + 1n)^2 = (2√m)^2
Z^2 + 2Z(1n) + (1n)^2 = 4m
Z^2 + 2Zn + n^2 = 4m
Now, divide both sides by 4 to solve for m:
m = (Z^2 + 2Zn + n^2) / 4
Therefore, m = (Z^2 + 2Zn + n^2) / 4.
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