Algebra,, Transpose:A =2(b-4c)➗ 5,Solve for c?

To solve for c, we need to isolate c on one side of the equation.

Given: A = 2(b-4c) / 5

First, multiply both sides by 5 to get rid of the denominator:

5A = 2(b-4c)

Next, distribute the 2 on the right side:

5A = 2b - 8c

Now, isolate c by moving 2b to the other side:

5A - 2b = -8c

Divide by -8 to solve for c:

c = (5A - 2b) / -8

Therefore, c = (5A - 2b) / -8.