A400g aluminum container containing 300g of water at 20 degrees Celsius is refrigerated to 0 degrees Celsius in 80 minutes. Determine the rate per minute at which heat is removed from the container ?

To determine the rate per minute at which heat is removed from the container, we can use the formula:

Q = mcΔT

Where:
Q = heat removed (in Joules)
m = mass of water (in kg)
c = specific heat capacity of water (4.18 J/g°C)
ΔT = change in temperature (in °C)

First, let's calculate the heat removed from the water:

m = 300g = 0.3kg
c = 4.18 J/g°C
ΔT = 20°C - 0°C = 20°C

Q = (0.3kg)(4.18 J/g°C)(20°C)
Q = 25.08 J

Next, let's calculate the rate per minute at which heat is removed from the container:

Rate = Q / time
Rate = 25.08 J / 80 minutes
Rate = 0.3135 J/min

Therefore, the rate per minute at which heat is removed from the container is 0.3135 J/min.