A tensile force 12N act on aluminium wire 2m and a diameter of 2.5mm.The wire is stretched with 0.3mm.Determine;? 1:stress? 2:stain of the wire?

To determine the stress and strain of the wire, we can use the following formulas:

1. Stress (σ) = Force (F) / Area (A)
2. Strain (ε) = Change in length (ΔL) / Original length (L)

First, let's calculate the area of the wire:

Area (A) = π * (radius)^2
Radius = diameter / 2 = 2.5mm / 2 = 1.25mm = 0.00125m
Area (A) = π * (0.00125m)^2

1. Stress (σ) = 12N / (π * (0.00125m)^2)

Now, let's calculate the strain:

Strain (ε) = 0.3mm / 2m

Note: We divide by 2m because the original length is given as 2m.

2. Strain (ε) = 0.3mm / 2m

Now, we can calculate the stress and strain:

1. Stress (σ) ≈ 12N / (π * (0.00125m)^2)
2. Strain (ε) ≈ 0.3mm / 2m