A quantity of a gas at a temperature of 15 degree Celsius is hearted at constant pressure until it's volume is doubled find final temperature of the gas?

To solve this problem, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (constant)
V = volume
n = number of moles of gas (constant)
R = ideal gas constant
T = temperature

Since the pressure is constant, we can rewrite the equation as:

V1/T1 = V2/T2

Given that the initial temperature (T1) is 15 degrees Celsius, we need to convert it to Kelvin by adding 273:

T1 = 15 + 273 = 288 K

Since the volume is doubled, V2 = 2V1

Now we can plug in the values into the equation:

V1/288 = 2V1/T2

Solving for T2:

T2 = 2 * 288 = 576 K

Therefore, the final temperature of the gas is 576 Kelvin.