a gas occupies 0.67l at 350k . what temperature is required a volume 45% ?

To find the temperature required for a volume of 45%, we can use the combined gas law equation:

(P1 * V1) / T1 = (P2 * V2) / T2

Given:
V1 = 0.67 L
T1 = 350 K
V2 = 0.45 * V1 = 0.45 * 0.67 L = 0.3015 L

Let's assume the pressure remains constant.

(P1 * V1) / T1 = (P2 * V2) / T2

Since the pressure is constant, we can simplify the equation to:

V1 / T1 = V2 / T2

Rearranging the equation to solve for T2:

T2 = (V2 * T1) / V1
T2 = (0.3015 L * 350 K) / 0.67 L

T2 ≈ 157.91 K

Therefore, a temperature of approximately 157.91 K is required for a volume of 45%.

What is kinetic energy

G

What is excel function

What is excel