A four _pole generator having wave _wound armature winding has 51 slots each slots containing 20 conductor What will be the voltage generated in the machine when driven at 1500 rpm assuming the Flux?

To calculate the voltage generated in the machine, we first need to determine the number of turns in the armature winding.

Given:
Number of poles (P) = 4
Number of slots (S) = 51
Number of conductors per slot (C) = 20

Number of turns per phase (T) = (S * C) / 2
T = (51 * 20) / 2
T = 510

Since the armature winding is wave-wound, the number of parallel paths (A) is equal to the number of poles (P).
A = P
A = 4

Total number of turns in the armature winding (T_total) = T * A
T_total = 510 * 4
T_total = 2040

The induced voltage (E) in the armature winding is given by the formula:
E = 4.44 * N * Φ * f
where:
N = number of turns in the armature winding
Φ = flux per pole in Weber
f = frequency of the generated voltage in Hz

Given:
N = 2040
f = 1500 rpm = 1500 / 60 = 25 Hz (since 1 Hz = 60 rpm)
Assuming the flux (Φ) = 0.06 Weber (typical value for a generator)

E = 4.44 * 2040 * 0.06 * 25
E = 11275.2 volts

Therefore, the voltage generated in the machine when driven at 1500 rpm assuming the flux is 11275.2 volts.