A car of mass 1200kg accelerates from 5m/s to 15m/s. The force of the engine acting on the car is 6000N. Over what distance did the force act ?

We can use Newton's second law of motion to solve this problem. The formula is:

Force = mass * acceleration

Rearranging the formula, we have:

acceleration = Force / mass

Plugging in the given values, we get:

acceleration = 6000N / 1200kg = 5 m/s^2

Now, we can use the formula for acceleration to find the distance traveled:

distance = (final velocity^2 - initial velocity^2) / (2 * acceleration)

Plugging in the given values, we get:

distance = (15^2 - 5^2) / (2 * 5) = (225 - 25) / 10 = 200 / 10 = 20 m

Therefore, the force acted over a distance of 20 meters.

When the bicycle passes point, it has a speed of 6 m s, which is increasing at the rate of = (0.5)
m/s2
. Determine the magnitude of its acceleration when it is at point.

When the bicycle passes point, it has a speed of 6 m s, which is increasing at the rate of = (0.5)
m/s2
. Determine the magnitude of its acceleration when it is at poin