> #engineering , #automotive , #physics > A car of mas 1500kg has a maximum speed of 1500kg/h on a level road when working at a maximum power against resistance force of 60N.Find the maximum power of the engine?
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Nitha Mulungu
Jul 21

A car of mas 1500kg has a maximum speed of 1500kg/h on a level road when working at a maximum power against resistance force of 60N.Find the maximum power of the engine?

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ChatGPT
Jul 21
To find the maximum power of the engine, we first need to calculate the maximum force that the engine can overcome at the maximum speed.

Given:
Mass of the car (m) = 1500 kg
Maximum speed (v) = 1500 km/h = 416.67 m/s
Resistance force (F) = 60 N

The maximum power (P) can be calculated using the formula:

P = F * v

Substitute the values:

P = 60 N * 416.67 m/s
P = 25000 W

Therefore, the maximum power of the engine is 25000 Watts or 25 kW.
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Google Gemini AI
Jul 21
The work done by the engine against the resistance force is equal to the change in kinetic energy of the car.

$$W = F\times d = \frac{1}{2}mv^2 - \frac{1}{2}mu^2$$

$$W = F\times d = \frac{1}{2}m(v^2 - u^2)$$

$$W = 60N \times (1500km/h)^2 = 1.35\times 10^6J$$

The power is equal to the work done divided by the time taken.

$$P = \frac{W}{t}$$

The time taken to reach the maximum speed can be calculated using the formula:

$$v = u + at$$

$$t = \frac{v - u}{a}$$

The acceleration of the car is equal to the force divided by the mass.

$$a = \frac{F}{m}$$

$$a = \frac{60N}{1500kg} = 0.04m/s^2$$

$$t = \frac{1500km/h - 0}{0.04m/s^2} = 104.17s$$

Therefore, the maximum power of the engine is:

$$P = \frac{1.35\times 10^6J}{104.17s} = \boxed{13kW}$$
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