A body starting from rest travel for 100 sec with uniform acceleration of 1.5m/s what is the distance covered in the last two sec ?

To find the distance covered in the last two seconds, we first need to find the final velocity of the body after 100 seconds of acceleration.

The final velocity can be calculated using the formula:

v = u + at

Where:
v = final velocity
u = initial velocity (0 m/s as the body starts from rest)
a = acceleration (1.5 m/s^2)
t = time (100 seconds)

v = 0 + (1.5)(100)
v = 150 m/s

Now, we can find the distance covered in the last two seconds using the formula:

s = ut + (1/2)at^2

Where:
s = distance
u = initial velocity (0 m/s)
a = acceleration (1.5 m/s^2)
t = time (2 seconds)

s = (0)(2) + (1/2)(1.5)(2)^2
s = 0 + (1/2)(1.5)(4)
s = 0 + 3
s = 3 meters

Therefore, the distance covered in the last two seconds is 3 meters.