A body of mass 58 gram is suspended at the 20 cm mark of a uniform meter rule.tge meter rule is adjusted on a pivot until it scales horizontally at 40 cm mark determine the mass of the meter rule ??

To solve this problem, we can use the principle of moments.

The moment of the body about the pivot point is equal to the moment of the meter rule about the pivot point.

Let the mass of the meter rule be M grams.

The moment of the body about the pivot point is given by:
58g * 20 cm

The moment of the meter rule about the pivot point is given by:
Mg * 40 cm

Since the meter rule is balanced horizontally, the two moments are equal:
58g * 20 cm = Mg * 40 cm

Solving for M, we get:
M = (58g * 20 cm) / 40 cm
M = 29 grams

Therefore, the mass of the meter rule is 29 grams.