A 70kg pilot flies his plane in a vertical loop of radius 600m and at the bottom of the loop he is travelling at 120m/s.What is the force applied on the pilots seat at this point?

At the bottom of the loop, the pilot is experiencing a centripetal acceleration towards the center of the loop. The force causing this acceleration is the net force acting on the pilot, which is the sum of the gravitational force and the normal force from the seat.

The centripetal force required to keep the pilot moving in a circular path is given by:

F = m * a

Where:
F = centripetal force
m = mass of the pilot (70kg)
a = centripetal acceleration

The centripetal acceleration is given by:

a = v^2 / r

Where:
v = velocity of the pilot (120m/s)
r = radius of the loop (600m)

Substitute the values into the equation:

a = (120)^2 / 600
a = 24 m/s^2

Now, calculate the centripetal force:

F = 70 * 24
F = 1680 N

Therefore, the force applied on the pilot's seat at the bottom of the loop is 1680 N.

Step 1: Determine the centripetal acceleration of the pilot.

The centripetal acceleration is given by:

```
a_c = v^2 / r
```

where:

- a_c is the centripetal acceleration
- v is the speed of the pilot
- r is the radius of the loop

Substituting the given values:

```
a_c = (120 m/s)^2 / 600 m
a_c = 24 m/s^2
```

Step 2: Calculate the force applied on the pilot's seat.

The force applied on the pilot's seat is given by:

```
F = m - a_c
```

where:

- F is the force
- m is the mass of the pilot
- a_c is the centripetal acceleration

Substituting the given values:

```
F = 70 kg - 24 m/s^2
F = 1680 N
```

Therefore, the force applied on the pilot's seat at the bottom of the loop is 1680 N.