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#electrical-engineering
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A 36A resistor and 18A resistor are connected in series across a 15V battery what is the 36A resistor, what is the 18A resistor and what is the power consumed ?
A 36A resistor and 18A resistor are connected in series across a 15V battery what is the 36A resistor, what is the 18A resistor and what is the power consumed ?
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ChatGPT
Aug 27
To find the resistance of the 36A resistor, we can use Ohm's Law:
V = I * R 15V = 36A * R R = 15V / 36A R = 0.4167 ohms
Therefore, the 36A resistor has a resistance of 0.4167 ohms.
To find the resistance of the 18A resistor, we can use the same formula:
V = I * R 15V = 18A * R R = 15V / 18A R = 0.8333 ohms
Therefore, the 18A resistor has a resistance of 0.8333 ohms.
To find the total power consumed by the circuit, we can use the formula:
P = V^2 / R_total P = 15V^2 / (0.4167 + 0.8333) ohms P = 15V^2 / 1.25 ohms P = 225W / 1.25 ohms P = 180 watts
Therefore, the total power consumed by the circuit is 180 watts.
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Google Gemini AI
Aug 27
Voltage across each resistor:
Since the resistors are connected in series, the voltage across each resistor is the same. Let's call this voltage V.
Current through each resistor:
The current through each resistor is also the same, since they are connected in series. We already know that the current through the circuit is 36A, so the current through both resistors is 36A.
Resistance of each resistor:
Using Ohm's law, we can calculate the resistance of each resistor:
``` Voltage = Current - Resistance ```
For the 36A resistor:
``` V = 36A - R36 ```
For the 18A resistor:
``` V = 36A - R18 ```
Since V is the same for both resistors, we can set these equations equal to each other and solve for R36:
``` R36 = 2 - R18 ```
Substituting the given value:
We are given that R18 = 18 ohms. Substituting this into the equation above, we get:
``` R36 = 2 - 18 ohms = 36 ohms ```
Voltage drop across each resistor:
Using Ohm's law again, we can calculate the voltage drop across each resistor: