A 30 kg shell is flying at 48 m/s when it explodes its one part of 18 kg stops while there was remaining part flies on what's the velocity of the latter? ?

To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the explosion is equal to the total momentum after the explosion.

Let's denote the velocity of the 18 kg part that stops as v1, and the velocity of the remaining part as v2.

Before the explosion:
Total momentum = (mass of the shell) * (velocity of the shell)
= (30 kg) * (48 m/s)
= 1440 kg·m/s

After the explosion:
Total momentum = (mass of the first part) * (velocity of the first part) + (mass of the second part) * (velocity of the second part)
= (18 kg) * (v1) + (12 kg) * (v2)

Since the first part stops, its velocity v1 is 0. Therefore, the equation becomes:
1440 kg·m/s = (18 kg) * (0 m/s) + (12 kg) * (v2)

Simplifying the equation:
1440 kg·m/s = 12 kg * v2
v2 = 1440 kg·m/s / 12 kg
v2 = 120 m/s

Therefore, the velocity of the remaining part after the explosion is 120 m/s.