> #technology , #electronics , #machinery > A 200kva rated transformer has a full load copper loss of 1.5kw and iron loss of 1kw determine the transformer efficiency at full load 0.85 power factor?
S
Shibela Shinga
Jun 1

A 200kva rated transformer has a full load copper loss of 1.5kw and iron loss of 1kw determine the transformer efficiency at full load 0.85 power factor?

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ChatGPT
Jun 1
First, we need to calculate the total losses in the transformer at full load:

Total losses = Copper loss + Iron loss
Total losses = 1.5 kW + 1 kW
Total losses = 2.5 kW

Next, we need to calculate the output power of the transformer at full load:

Output power = 200 kVA * 0.85
Output power = 170 kW

Now, we can calculate the efficiency of the transformer at full load:

Efficiency = (Output power / (Output power + Total losses)) * 100
Efficiency = (170 kW / (170 kW + 2.5 kW)) * 100
Efficiency = (170 / 172.5) * 100
Efficiency = 0.985 * 100
Efficiency = 98.5%

Therefore, the efficiency of the transformer at full load with a 0.85 power factor is 98.5%.
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G
Google Gemini AI
Jun 1
Given:

- Transformer rating: 200 kVA
- Full load copper loss: 1.5 kW
- Full load iron loss: 1 kW
- Power factor: 0.85

Formula for transformer efficiency:

```
η = (Output power) / (Input power)
```

Calculating output power:

Output power = Transformer rating - Power factor
Output power = 200 kVA - 0.85
Output power = 170 kW

Calculating total losses:

Total losses = Copper loss + Iron loss
Total losses = 1.5 kW + 1 kW
Total losses = 2.5 kW

Calculating input power:

Input power = Output power + Total losses
Input power = 170 kW + 2.5 kW
Input power = 172.5 kW

Calculating efficiency:

```
η = (Output power) / (Input power)
η = 170 kW / 172.5 kW
η = 0.986
```

Therefore, the transformer efficiency at full load 0.85 power factor is 98.6%.
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