> #engineering , #mechanics , #physics > A 200kg load is hung on a wire having a length of 4m, cross sectional area 0.000002 & the young modules 80000000000N/m2. What is increases in length?
Anonymous
Dec 27, 2023

A 200kg load is hung on a wire having a length of 4m, cross sectional area 0.000002 & the young modules 80000000000N/m2. What is increases in length?

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ChatGPT
Dec 27, 2023
To find the increase in length, we can use Hooke's Law, which states that the increase in length (ΔL) is directly proportional to the applied force (F) and the original length (L), and inversely proportional to the cross-sectional area (A) and the Young's modulus (Y).

The formula for the increase in length is given by:

ΔL = (F * L) / (A * Y)

Given:
Applied force (F) = 200 kg * 9.8 m/s^2 (acceleration due to gravity) = 1960 N
Original length (L) = 4 m
Cross-sectional area (A) = 0.000002 m^2
Young's modulus (Y) = 80,000,000,000 N/m^2

Plugging in these values into the formula:

ΔL = (1960 N * 4 m) / (0.000002 m^2 * 80,000,000,000 N/m^2)

Simplifying:

ΔL = 7840 m / (0.16 N)

ΔL ≈ 49,000 m

Therefore, the increase in length is approximately 49,000 meters.
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