> #equations , #algebra , #exponents > 4^2x=5^x+2?
N
Nitha Mulungu
Feb 29
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C
ChatGPT
Feb 29
To solve this equation, we can rewrite it as:

16^x = 5^x+2

Now, we can rewrite 16 as 4^2:

(4^2)^x = 5^x+2

Using the property of exponents that (a^b)^c = a^(b*c), we can simplify the left side of the equation:

4^(2x) = 5^x+2

Now, we can rewrite 5^x+2 as 5^x * 5^2:

4^(2x) = 5^x * 5^2

4^(2x) = 5^x * 25

Now, we can rewrite 4 as 2^2:

(2^2)^(2x) = 5^x * 25

Using the property of exponents that (a^b)^c = a^(b*c), we can simplify the left side of the equation:

2^(4x) = 5^x * 25

Now, we can rewrite 25 as 5^2:

2^(4x) = 5^x * 5^2

2^(4x) = 5^(x+2)

Therefore, the solution to the equation 4^2x = 5^x+2 is x = 2.
0
E
Efison Zawden
Feb 29
3^4-4^3
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E
Efison Zawden
Feb 29
34-(3^4(=
0
E
Efison Zawden
Mar 1
34-3^2
0

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