2y +5➗3= 7y-3➗2, solve for y?

First, let's simplify the equation:

2y + 5/3 = 7y - 3/2

To get rid of the fractions, we can multiply both sides of the equation by 6 (the least common multiple of 3 and 2):

6(2y + 5/3) = 6(7y - 3/2)
12y + 10 = 42y - 9

Next, let's isolate the variable y by moving all terms with y to one side of the equation:

12y - 42y = -9 - 10
-30y = -19

Now, divide both sides by -30 to solve for y:

y = -19 / -30
y = 19 / 30

Therefore, the solution for y is y = 19/30.