Anonymous
May 14
20cm3 of a solution of hydroxide of 1 completely neutralizes 17.5cm3 sulphur (vI) acid.calculate the concentration in moles/litre of solution of hydroxide?
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May 14
To find the concentration in moles/liter of the hydroxide solution, we first need to determine the number of moles of sulfuric acid that were neutralized by the hydroxide.
From the given information, we know that 20 cm3 of the hydroxide solution neutralizes 17.5 cm3 of sulfuric acid. This means that the two solutions react in a 1:1 ratio.
Now, we need to calculate the number of moles of sulfuric acid that were neutralized:
Volume of sulfuric acid = 17.5 cm3
Concentration of sulfuric acid = 1 mole/liter (since it is a VI acid)
Number of moles of sulfuric acid = (Volume x Concentration) / 1000
Number of moles of sulfuric acid = (17.5 x 1) / 1000
Number of moles of sulfuric acid = 0.0175 moles
Since the reaction is 1:1, the number of moles of hydroxide that neutralized the sulfuric acid is also 0.0175 moles.
Now, we need to calculate the concentration of the hydroxide solution:
Volume of hydroxide solution = 20 cm3 = 0.02 liters
Concentration of hydroxide solution = Number of moles / Volume
Concentration of hydroxide solution = 0.0175 moles / 0.02 liters
Concentration of hydroxide solution = 0.875 moles/liter
Therefore, the concentration of the hydroxide solution is 0.875 moles/liter.
From the given information, we know that 20 cm3 of the hydroxide solution neutralizes 17.5 cm3 of sulfuric acid. This means that the two solutions react in a 1:1 ratio.
Now, we need to calculate the number of moles of sulfuric acid that were neutralized:
Volume of sulfuric acid = 17.5 cm3
Concentration of sulfuric acid = 1 mole/liter (since it is a VI acid)
Number of moles of sulfuric acid = (Volume x Concentration) / 1000
Number of moles of sulfuric acid = (17.5 x 1) / 1000
Number of moles of sulfuric acid = 0.0175 moles
Since the reaction is 1:1, the number of moles of hydroxide that neutralized the sulfuric acid is also 0.0175 moles.
Now, we need to calculate the concentration of the hydroxide solution:
Volume of hydroxide solution = 20 cm3 = 0.02 liters
Concentration of hydroxide solution = Number of moles / Volume
Concentration of hydroxide solution = 0.0175 moles / 0.02 liters
Concentration of hydroxide solution = 0.875 moles/liter
Therefore, the concentration of the hydroxide solution is 0.875 moles/liter.
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Google Gemini AI
May 14
Step 1: Calculate the moles of sulfur (VI) acid used.
Moles of H2SO4 = Volume of H2SO4 (L) x Concentration of H2SO4 (M)
Moles of H2SO4 = 17.5 cm³ × (1 L / 1000 cm³) × (0.1 M) = 0.00175 mol
Step 2: Determine the mole ratio between NaOH and H2SO4.
The balanced chemical equation for the reaction is:
2 NaOH + H2SO4 → Na2SO4 + 2 H2O
From the equation, we see that 2 moles of NaOH react with 1 mole of H2SO4. So, the mole ratio is 2:1.
Step 3: Calculate the moles of NaOH used.
Moles of NaOH = Moles of H2SO4 × Mole ratio
Moles of NaOH = 0.00175 mol × 2 = 0.0035 mol
Step 4: Calculate the concentration of NaOH solution.
Concentration of NaOH = Moles of NaOH / Volume of NaOH solution
Concentration of NaOH = 0.0035 mol / 20 cm³ × (1 L / 1000 cm³) = 0.175 M
Therefore, the concentration of the hydroxide solution is 0.175 mol/L.
Moles of H2SO4 = Volume of H2SO4 (L) x Concentration of H2SO4 (M)
Moles of H2SO4 = 17.5 cm³ × (1 L / 1000 cm³) × (0.1 M) = 0.00175 mol
Step 2: Determine the mole ratio between NaOH and H2SO4.
The balanced chemical equation for the reaction is:
2 NaOH + H2SO4 → Na2SO4 + 2 H2O
From the equation, we see that 2 moles of NaOH react with 1 mole of H2SO4. So, the mole ratio is 2:1.
Step 3: Calculate the moles of NaOH used.
Moles of NaOH = Moles of H2SO4 × Mole ratio
Moles of NaOH = 0.00175 mol × 2 = 0.0035 mol
Step 4: Calculate the concentration of NaOH solution.
Concentration of NaOH = Moles of NaOH / Volume of NaOH solution
Concentration of NaOH = 0.0035 mol / 20 cm³ × (1 L / 1000 cm³) = 0.175 M
Therefore, the concentration of the hydroxide solution is 0.175 mol/L.
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