0.5 m in mercury manometer is equal to how many N/m²?

To convert from meters of mercury to pascals (N/m²), we can use the conversion factor:

1 m of mercury = 13332.2 N/m²

Therefore, 0.5 m of mercury is equal to:

0.5 m * 13332.2 N/m² = 6666.1 N/m²

So, 0.5 m in a mercury manometer is equal to 6666.1 N/m².

Pressure due to a liquid column is given as,
P = h - d - g

Where,
P is the pressure
h is the height of the liquid column
d is the density of the liquid
g is the acceleration due to gravity

In this case,
h = 0.5 m
d = 13600 kg/m³ (density of mercury)
g = 9.81 m/s²

Substituting these values into the formula, we get:
P = 0.5 m - 13600 kg/m³ - 9.81 m/s²
P = 66736 N/m²

Therefore, 0.5 m in mercury manometer is equal to 66736 N/m².