Two balls are drawn (drawn replacement) from a bag containing 12 red, 3 white and 1 blue balls.what is the probability that both are red?

The total number of balls in the bag is 12 + 3 + 1 = 16.

The probability of drawing a red ball on the first draw is 12/16.

Since the ball is drawn with replacement, the probability of drawing a red ball on the second draw is also 12/16.

Therefore, the probability of drawing two red balls is (12/16) * (12/16) = 144/256 = 9/16.

So, the probability that both balls drawn are red is 9/16.

The probability of drawing a red ball on the first draw is 12/16 = 3/4. Since the balls are drawn with replacement, the probability of drawing a red ball on the second draw is also 3/4. The probability of drawing both a red ball on the first draw and a red ball on the second draw is 3/4 - 3/4 = 9/16. Therefore, the probability of drawing both balls red is 9/16.