Prepare 100mls of 0.025N AgNO3 stock solution. Calculate how much volume of 0.1AgNO3 stock solution is needed to prepare 100mls of 0.025N AgNO3?

To prepare 100mls of 0.025N AgNO3 stock solution, we can use the formula:

C1V1 = C2V2

Where:
C1 = concentration of stock solution 1
V1 = volume of stock solution 1
C2 = concentration of stock solution 2
V2 = volume of stock solution 2

Given:
C1 = 0.1N (concentration of 0.1N AgNO3 stock solution)
V1 = ?
C2 = 0.025N (desired concentration of AgNO3 stock solution)
V2 = 100ml

Plugging in the values:

0.1V1 = 0.025(100)
0.1V1 = 2.5
V1 = 2.5 / 0.1
V1 = 25ml

Therefore, 25ml of 0.1N AgNO3 stock solution is needed to prepare 100mls of 0.025N AgNO3 stock solution.

Calculation of required volume of 0.1N AgNO3 stock solution:

Step 1: Calculate the number of moles of AgNO3 needed for 100 mL of 0.025N solution.

Molarity (M) = Number of moles of solute / volume of solution in liters

0.025 N = Number of moles of AgNO3 / 0.1 L

Number of moles of AgNO3 = 0.025 N × 0.1 L = 0.0025 moles

Step 2: Calculate the volume of 0.1N AgNO3 stock solution required to provide 0.0025 moles of AgNO3.

M1 × V1 = M2 × V2

where:

- M1 is the molarity of the stock solution (0.1 N)
- V1 is the volume of the stock solution we need to find
- M2 is the desired molarity of the new solution (0.025 N)
- V2 is the volume of the new solution (100 mL)

0.1 N × V1 = 0.025 N × 100 mL

V1 = (0.025 N × 100 mL) / 0.1 N

V1 = 25 mL

Therefore, to prepare 100 mL of 0.025N AgNO3 solution, you will need to take 25 mL of the 0.1N AgNO3 stock solution and dilute it with enough water to make a total volume of 100 mL.