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Find the area of shaded area ,if ABCD is a square of side 10.5cm .and APD and BPC are semicircles .(use π=²²/⁷?
venkateswara rao boppudi
Jan 18
Find the area of shaded area ,if ABCD is a square of side 10.5cm .and APD and BPC are semicircles .(use π=²²/⁷?
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Jan 18
To find the area of the shaded region, we need to subtract the areas of the two semicircles from the area of the square.
The area of a square is given by the formula A = s^2, where s is the length of a side. In this case, s = 10.5 cm, so the area of the square is A = (10.5 cm)^2 = 110.25 cm^2.
The area of a semicircle is given by the formula A = (π/2) * r^2, where r is the radius. In this case, the radius is half the length of the side of the square, so r = 10.5 cm / 2 = 5.25 cm.
Using the given value of π = 22/7, the area of one semicircle is A = (22/7) * (5.25 cm)^2 = 90.75 cm^2.
Since there are two semicircles, the total area of the two semicircles is 2 * 90.75 cm^2 = 181.5 cm^2.
Finally, to find the shaded area, we subtract the area of the two semicircles from the area of the square: 110.25 cm^2 - 181.5 cm^2 = -71.25 cm^2.
However, it is not possible for the shaded area to be negative. Therefore, there may be an error in the given information or calculations. Please double-check the values and calculations provided.
The area of a square is given by the formula A = s^2, where s is the length of a side. In this case, s = 10.5 cm, so the area of the square is A = (10.5 cm)^2 = 110.25 cm^2.
The area of a semicircle is given by the formula A = (π/2) * r^2, where r is the radius. In this case, the radius is half the length of the side of the square, so r = 10.5 cm / 2 = 5.25 cm.
Using the given value of π = 22/7, the area of one semicircle is A = (22/7) * (5.25 cm)^2 = 90.75 cm^2.
Since there are two semicircles, the total area of the two semicircles is 2 * 90.75 cm^2 = 181.5 cm^2.
Finally, to find the shaded area, we subtract the area of the two semicircles from the area of the square: 110.25 cm^2 - 181.5 cm^2 = -71.25 cm^2.
However, it is not possible for the shaded area to be negative. Therefore, there may be an error in the given information or calculations. Please double-check the values and calculations provided.
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