> #molarity , #poh-calculation , #chemistry , #ph-calculation , #concentration-calculations > Ba(OH)2 contains 4.285gram of Ba (OH)2 in 100mL of solution the find molarity, PH,POH,[H^+] ?
Anonymous
Mar 27

Ba(OH)2 contains 4.285gram of Ba (OH)2 in 100mL of solution the find molarity, PH,POH,[H^+] ?

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Mar 27
To find the molarity of Ba(OH)2 in the solution, we first need to calculate the number of moles of Ba(OH)2 present in 4.285 grams.

The molar mass of Ba(OH)2 is:
Ba = 137.33 g/mol
O = 16.00 g/mol
H = 1.01 g/mol

Molar mass of Ba(OH)2 = 137.33 + 2(16.00) + 2(1.01) = 171.35 g/mol

Number of moles of Ba(OH)2 = 4.285 g / 171.35 g/mol = 0.025 moles

Now, we need to calculate the molarity of Ba(OH)2 in the solution:

Molarity = moles of solute / volume of solution in liters
Molarity = 0.025 moles / 0.1 L = 0.25 M

Next, we can calculate the pOH of the solution:

pOH = -log[OH-]
pOH = -log(0.25) = 0.60

Since pH + pOH = 14, we can calculate the pH of the solution:

pH = 14 - pOH = 14 - 0.60 = 13.40

Finally, we can calculate the concentration of [H+] in the solution using the equation:

[H+] = Kw / [OH-]
[H+] = 1.0 x 10^-14 / 0.25 = 4.0 x 10^-14 M

Therefore, the molarity of Ba(OH)2 in the solution is 0.25 M, the pH is 13.40, the pOH is 0.60, and the concentration of [H+] is 4.0 x 10^-14 M.
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