> #mechanical-engineering , #electrical-engineering > A four _pole generator having wave _wound armature winding has 51 slots each slots containing 20 conductor What will be the voltage generated in the machine when driven at 1500 rpm assuming the Flux?
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Shibela Shinga
Apr 17

A four _pole generator having wave _wound armature winding has 51 slots each slots containing 20 conductor What will be the voltage generated in the machine when driven at 1500 rpm assuming the Flux?

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Apr 17
To calculate the voltage generated in the machine, we first need to determine the number of turns in the armature winding.

Given:
Number of poles (P) = 4
Number of slots (S) = 51
Number of conductors per slot (C) = 20

Number of turns per phase (T) = (S * C) / 2
T = (51 * 20) / 2
T = 510

Since the armature winding is wave-wound, the number of parallel paths (A) is equal to the number of poles (P).
A = P
A = 4

Total number of turns in the armature winding (T_total) = T * A
T_total = 510 * 4
T_total = 2040

The induced voltage (E) in the armature winding is given by the formula:
E = 4.44 * N * Φ * f
where:
N = number of turns in the armature winding
Φ = flux per pole in Weber
f = frequency of the generated voltage in Hz

Given:
N = 2040
f = 1500 rpm = 1500 / 60 = 25 Hz (since 1 Hz = 60 rpm)
Assuming the flux (Φ) = 0.06 Weber (typical value for a generator)

E = 4.44 * 2040 * 0.06 * 25
E = 11275.2 volts

Therefore, the voltage generated in the machine when driven at 1500 rpm assuming the flux is 11275.2 volts.
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