A bullet leaves a rifle with a velocity of 452m/s.While accelerating through the barrel of the rifle, the bullet moves 0.93m Determine the acceleration of the bullet ?

To determine the acceleration of the bullet, we can use the equation of motion:

v^2 = u^2 + 2as

Where:
v = final velocity (452 m/s)
u = initial velocity (0 m/s, as the bullet starts from rest)
a = acceleration (unknown)
s = displacement (0.93 m)

Rearranging the equation, we get:

a = (v^2 - u^2) / (2s)

Substituting the given values, we have:

a = (452^2 - 0^2) / (2 * 0.93)
a = 204,304 / 1.86
a ≈ 109,935.48 m/s^2

Therefore, the acceleration of the bullet is approximately 109,935.48 m/s^2.