0.5 m in mercury manometer between each arm 8s equal to how many N/m², kph,and athmosphere?

To convert the pressure difference in a mercury manometer from meters of mercury to other units, we can use the following conversions:

1 m of mercury = 13332.2 N/m²
1 m of mercury = 101325 Pa
1 m of mercury = 760 mmHg
1 m of mercury = 29.92 inHg
1 m of mercury = 1.333 atm

Given that the pressure difference in the manometer is 0.5 m of mercury, we can convert this to other units:

0.5 m of mercury = 0.5 * 13332.2 N/m² = 6666.1 N/m²
0.5 m of mercury = 0.5 * 101325 Pa = 50662.5 Pa
0.5 m of mercury = 0.5 * 760 mmHg = 380 mmHg
0.5 m of mercury = 0.5 * 29.92 inHg = 14.96 inHg
0.5 m of mercury = 0.5 * 1.333 atm = 0.6665 atm

Therefore, the pressure difference of 0.5 m of mercury in the manometer is equal to:
- 6666.1 N/m²
- 50662.5 Pa
- 380 mmHg
- 14.96 inHg
- 0.6665 atm

1. N/m² (Newtons per square meter)

0.5 m of mercury in a manometer corresponds to a pressure difference of:

```
P = ρgh = (13600 kg/m³) - (9.81 m/s²) - (0.5 m) = 67026 Pa
```

Therefore, 0.5 m of mercury is equal to 67,026 N/m².

2. km/h (kilometers per hour)

This conversion is not applicable as pressure is not a measure of speed.

3. Atmosphere (atm)

1 atmosphere is defined as the pressure exerted by a column of mercury 760 mm high. Therefore, 0.5 m of mercury is equal to:

```
P = 0.5 m / 0.76 m = 0.6579 atm
```

Therefore, 0.5 m of mercury is equal to 0.6579 atmospheres.